9t^2=121

Solution for 9t^2=121 equation:

9t^2=121

We move all terms to the left:

9t^2-(121)=0

a = 9; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·9·(-121)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-66}{2*9}=\frac{-66}{18}
=-3+2/3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+66}{2*9}=\frac{66}{18}
=3+2/3
$